2006 Paper 2 Q7

Year: 2006
Paper: 2
Question Number: 7

Course: LFM Pure and Mechanics
Section: Parametric equations

Difficulty: 1600.0 Banger: 1500.0

Problem

An ellipse has equation $\dfrac{x^2}{a^2} +\dfrac {y^2}{b^2} = 1$. Show that the equation of the tangent at the point \((a\cos\alpha, b\sin\alpha)\) is \[ y=- \frac {b \cot \alpha} a \, x + b\, {\rm cosec\,}\alpha\,. \] The point \(A\) has coordinates \((-a,-b)\), where \(a\) and \(b\) are positive. The point \(E\) has coordinates \((-a,0)\) and the point \(P\) has coordinates \((a,kb)\), where \(0 < k < 1\). The line through \(E\) parallel to \(AP\) meets the line \(y=b\) at the point \(Q\). Show that the line \(PQ\) is tangent to the above ellipse at the point given by \(\tan(\alpha/2)=k\). Determine by means of sketches, or otherwise, whether this result holds also for \(k=0\) and \(k=1\).

No solution available for this problem.

Rating Information

Difficulty Rating: 1600.0

Difficulty Comparisons: 0

Banger Rating: 1500.0

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Problem source
An ellipse has equation $\dfrac{x^2}{a^2}  +\dfrac {y^2}{b^2} =
1$. Show that 
the equation of the tangent at the point $(a\cos\alpha, b\sin\alpha)$ is
\[
y=- \frac {b  \cot \alpha} a \, x + b\, {\rm cosec\,}\alpha\,.
\]

The point $A$ has coordinates $(-a,-b)$, where $a$ and $b$ are
positive. The point $E$ has coordinates $(-a,0)$
and the point $P$ has coordinates $(a,kb)$, where $0 < k < 1$.
The line through $E$ parallel to  $AP$ meets the line $y=b$ at
the point $Q$. Show that the line $PQ$ is tangent to the above ellipse
at the point given by $\tan(\alpha/2)=k$.
Determine by means of sketches, or otherwise, whether this result
holds also for $k=0$ and $k=1$.