1991 Paper 2 Q6

Year: 1991
Paper: 2
Question Number: 6

Course: LFM Pure
Section: Integration

Difficulty: 1600.0 Banger: 1485.5

Problem

Show by means of a sketch, or otherwise, that if \(0\leqslant\mathrm{f}(y)\leqslant\mathrm{g}(y)\) for \(0\leqslant y\leqslant x\) then \[ 0\leqslant\int_{0}^{x}\mathrm{f}(y)\,\mathrm{d}y\leqslant\int_{0}^{x}\mathrm{g}(y)\,\mathrm{d}y. \] Starting from the inequality \(0\leqslant\cos y\leqslant1,\) or otherwise, prove that if \(0\leqslant x\leqslant\frac{1}{2}\pi\) then \(0\leqslant\sin x\leqslant x\) and \(\cos x\geqslant1-\frac{1}{2}x^{2}.\) Deduce that \[ \frac{1}{1800}\leqslant\int_{0}^{\frac{1}{10}}\frac{x}{(2+\cos x)^{2}}\,\mathrm{d}x\leqslant\frac{1}{1797}. \] Show further that if \(0\leqslant x\leqslant\frac{1}{2}\pi\) then \(\sin x\geqslant x-\frac{1}{6}x^{3}.\) Hence prove that \[ \frac{1}{3000}\leqslant\int_{0}^{\frac{1}{10}}\frac{x^{2}}{(1-x+\sin x)^{2}}\,\mathrm{d}x\leqslant\frac{2}{5999}. \]

No solution available for this problem.

Rating Information

Difficulty Rating: 1600.0

Difficulty Comparisons: 0

Banger Rating: 1485.5

Banger Comparisons: 1

Show LaTeX source
Problem source
Show by means of a sketch, or otherwise, that if $0\leqslant\mathrm{f}(y)\leqslant\mathrm{g}(y)$
	for $0\leqslant y\leqslant x$ then 
	\[
	0\leqslant\int_{0}^{x}\mathrm{f}(y)\,\mathrm{d}y\leqslant\int_{0}^{x}\mathrm{g}(y)\,\mathrm{d}y.
	\]
	Starting from the inequality $0\leqslant\cos y\leqslant1,$ or otherwise,
	prove that if $0\leqslant x\leqslant\frac{1}{2}\pi$ then $0\leqslant\sin x\leqslant x$
	and $\cos x\geqslant1-\frac{1}{2}x^{2}.$ Deduce that 
	\[
	\frac{1}{1800}\leqslant\int_{0}^{\frac{1}{10}}\frac{x}{(2+\cos x)^{2}}\,\mathrm{d}x\leqslant\frac{1}{1797}.
	\]
	Show further that if $0\leqslant x\leqslant\frac{1}{2}\pi$ then $\sin x\geqslant x-\frac{1}{6}x^{3}.$
	Hence prove that 
	\[
	\frac{1}{3000}\leqslant\int_{0}^{\frac{1}{10}}\frac{x^{2}}{(1-x+\sin x)^{2}}\,\mathrm{d}x\leqslant\frac{2}{5999}.
	\]