2001 Paper 1 Q6

Year: 2001
Paper: 1
Question Number: 6

Course: LFM Pure and Mechanics
Section: Integration as Area

Difficulty: 1500.0 Banger: 1516.0

Problem

A spherical loaf of bread is cut into parallel slices of equal thickness. Show that, after any number of the slices have been eaten, the area of crust remaining is proportional to the number of slices remaining. A European ruling decrees that a parallel-sliced spherical loaf can only be referred to as `crusty' if the ratio of volume \(V\) (in cubic metres) of bread remaining to area \(A\) (in square metres) of crust remaining after any number of slices have been eaten satisfies \(V/A<1\). Show that the radius of a crusty parallel-sliced spherical loaf must be less than \(2\frac23\) metres. [{\sl The area \(A\) and volume \(V\) formed by rotating a curve in the \(x\)--\(y\) plane round the \(x\)-axis from \(x=-a\) to \(x=-a+t\) are given by \[ A= 2\pi\int_{-a}^{-a+t} { y}\left( 1+ \Big(\frac{\d {y}}{\d x}\Big)^2\right)^{\frac12} \d x\;, \ \ \ \ \ \ \ \ \ \ \ V= \pi \int_{-a}^{-a+t} {y}^2 \d x \;. \ \ ] \] }

No solution available for this problem.

Rating Information

Difficulty Rating: 1500.0

Difficulty Comparisons: 0

Banger Rating: 1516.0

Banger Comparisons: 1

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Problem source
A spherical loaf of bread is cut into parallel slices of  equal thickness. Show that,
after any number of the  slices have been eaten, 
the area of crust remaining is proportional to the number of slices remaining.
A European ruling decrees that a parallel-sliced
spherical loaf can only be referred to as `crusty' if the ratio of
volume $V$ (in cubic metres) of bread remaining to area $A$ (in square metres)
of  crust remaining after any number of slices have been eaten satisfies
$V/A<1$. Show that the radius of a crusty parallel-sliced
spherical loaf must be less than $2\frac23$ metres.
[{\sl The area $A$ and volume $V$ formed by rotating a curve in the $x$--$y$ plane 
round the $x$-axis from $x=-a$ to $x=-a+t$ 
are given by
\[
A= 2\pi\int_{-a}^{-a+t} 
{ y}\left( 1+ \Big(\frac{\d {y}}{\d x}\Big)^2\right)^{\frac12}
\d x\;,
\ \ \ \ \ \ \ \ \ \ \
V= \pi \int_{-a}^{-a+t} {y}^2 \d x \;. \ \ 
]
\]
}