39 problems found
Solution:
In this question, you need not consider issues of convergence. For positive integer \(n\) let \[\mathrm{f}(n) = \frac{1}{n+1} + \frac{1}{(n+1)(n+2)} + \frac{1}{(n+1)(n+2)(n+3)} + \ldots\] and \[\mathrm{g}(n) = \frac{1}{n+1} - \frac{1}{(n+1)(n+2)} + \frac{1}{(n+1)(n+2)(n+3)} - \ldots\,.\]
Let \(\mathrm{h}(z) = nz^6 + z^5 + z + n\), where \(z\) is a complex number and \(n \geqslant 2\) is an integer.
A sequence \(u_k\), for integer \(k \geqslant 1\), is defined as follows. \[ u_1 = 1 \] \[ u_{2k} = u_k \text{ for } k \geqslant 1 \] \[ u_{2k+1} = u_k + u_{k+1} \text{ for } k \geqslant 1 \]
Consider the following steps in a proof that \(\sqrt{2} + \sqrt{3}\) is irrational.
Solution:
The sequence \(u_0, u_1, \ldots\) is said to be a constant sequence if \(u_n = u_{n+1}\) for \(n = 0, 1, 2, \ldots\). The sequence is said to be a sequence of period 2 if \(u_n = u_{n+2}\) for \(n = 0, 1, 2, \ldots\) and the sequence is not constant.
Solution:
The \(n\)th degree polynomial P\((x)\) is said to be reflexive if:
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In this question, you may assume that, if a continuous function takes both positive and negative values in an interval, then it takes the value \(0\) at some point in that interval.
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For each non-negative integer \(n\), the polynomial \(\f_n\) is defined by \[ \f_n(x) = 1 + x + \frac{x^2}{2!} + \frac {x^3}{3!} + \cdots + \frac{x^n}{n!} \]
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