2007 Paper 1 Q11

Year: 2007
Paper: 1
Question Number: 11

Course: LFM Pure and Mechanics
Section: Projectiles

Difficulty: 1516.0 Banger: 1484.0

Problem

A smooth, straight, narrow tube of length \(L\) is fixed at an angle of \(30^\circ\) to the horizontal. A~particle is fired up the tube, from the lower end, with initial velocity \(u\). When the particle reaches the upper end of the tube, it continues its motion until it returns to the same level as the lower end of the tube, having travelled a horizontal distance \(D\) after leaving the tube. Show that \(D\) satisfies the equation \[ 4gD^2 - 2 \sqrt{3} \left( u^2 - Lg \right)D - 3L \left( u^2 - gL \right) = 0 \] and hence that \[ \frac{{\rm d}D}{ {\rm d}L} = - \frac{ 2\sqrt{3}gD - 3(u^2-2gL)} { 8gD - 2 \sqrt{3} \left(u^2 - gL \right)}. \] The final horizontal displacement of the particle from the lower end of the tube is \(R\). Show that \(\dfrac{\d R}{\d L} = 0\) when \(2D = L \sqrt 3\), and determine, in terms of \(u\) and \(g\), the corresponding value of \(R\).

No solution available for this problem.

Examiner's report
— 2007 STEP 1, Question 11
Least Popular Diagrams strongly recommended

Hardly any attempts at this question were seen. It was remarkable how few diagrams were seen; it is always much easier for both the candidate and the examiner if answers begin with a labelled diagram.

There were significantly more candidates attempting this paper this year (an increase of nearly 50%), but many found it to be very difficult and only achieved low scores. In particular, the level of algebraic skill required by the questions was often lacking. The examiners' express their concern that this was the case despite a conscious effort to make the paper more accessible than last year's. At this level, the fluent, confident and correct handling of mathematical symbols (and numbers) is necessary and is expected; many good starts to questions soon became unstuck after a simple slip. Graph sketching was usually poor: if future candidates wanted to improve one particular skill, they would be well advised to develop this. There were of course some excellent scripts, full of logical clarity and perceptive insight. It was pleasing to note that the applied questions were more popular this year, and many candidates scored well on at least one of these. It was however surprising how rarely answers to questions such as 5, 9, 10, 11 and 12 began with a diagram. However, the examiners were left with the overall feeling that some candidates had not prepared themselves well for the examination. The use of past papers to ensure adequate preparation is strongly recommended. A student's first exposure to STEP questions can be a daunting, demanding experience; it is a shame if that takes place during a public examination on which so much rides. Further, and fuller, discussion of the solutions to these questions can be found in the Hints and Answers document.

Source: Cambridge STEP 2007 Examiner's Report · 2007-full.pdf
Rating Information

Difficulty Rating: 1516.0

Difficulty Comparisons: 1

Banger Rating: 1484.0

Banger Comparisons: 1

Show LaTeX source
Problem source
A smooth, straight, narrow tube of length $L$
 is fixed at an angle of $30^\circ$ to the horizontal.
A~particle is fired up the tube, from the lower end,
with initial velocity $u$.
When the particle reaches the upper end of the tube,
it continues its motion until it returns to the same
level as the lower end of the tube, having travelled 
a horizontal distance $D$ after leaving the tube.
Show that $D$ satisfies the equation
\[
4gD^2 - 2 \sqrt{3} \left( u^2 - Lg \right)D
- 3L \left( u^2 - gL \right) = 0
\]
and hence that 
\[ 
\frac{{\rm d}D}{ {\rm d}L}
= - \frac{ 2\sqrt{3}gD - 3(u^2-2gL)}
{ 8gD - 2 \sqrt{3} \left(u^2 - gL \right)}.
\]

The final  horizontal displacement 
of the particle from the lower end of the tube is $R$. 
Show that $\dfrac{\d R}{\d L} = 0$ when $2D = L \sqrt 3$, 
and determine, in terms of $u$ and $g$,
 the corresponding value of $R$.