Year: 2006
Paper: 1
Question Number: 8
Course: LFM Pure
Section: Introduction to trig
No solution available for this problem.
Difficulty Rating: 1500.0
Difficulty Comparisons: 0
Banger Rating: 1484.0
Banger Comparisons: 1
{\it Note that the volume of a
tetrahedron is equal to $\frac1 3$ $\times$
the area of the base $\times$ the height.}
The points $O$, $A$, $B$ and $C$ have coordinates $(0,0,0)$, $(a,0,0)$, $(0,b,0)$
and $(0,0,c)$, respectively, where $a$, $b$ and $c$ are positive.
\begin{questionparts}
\item Find, in terms of $a$, $b$ and $c$, the volume of the tetrahedron
$OABC$.
\item
Let angle $ACB = \theta$. Show that
\[
\cos\theta =
\frac {c^2}
{
{ \sqrt{\vphantom{ \dot b}
(a^2+c^2)(b^2+c^2)} }
^{\vphantom A}
\ }
\]
and find, in terms of $a$, $b$ and $c$, the area of triangle $ABC$.
% is
%$\displaystyle \tfrac12 \sqrt{ \vphantom{\dot A } a^2b^2 +b^2c^2 + c^2 a^2 \;} \;$.
\end{questionparts}
Hence show that $d$, the perpendicular distance of the origin from
the triangle $ABC$, satisfies
\[
\frac 1{d^2} = \frac 1 {a^2} + \frac 1 {b^2} + \frac 1 {c^2} \,.
\]