Year: 2004
Paper: 2
Question Number: 3
Course: LFM Stats And Pure
Section: Curve Sketching
Difficulty Rating: 1600.0
Difficulty Comparisons: 0
Banger Rating: 1600.7
Banger Comparisons: 10
The curve $C$ has equation
$$
y = x(x+1)(x-2)^4.
$$
Determine the coordinates of all the stationary points of $C$ and the nature of each. Sketch $C$.
In separate diagrams draw sketches of the curves whose equations are:
\begin{questionparts}
\item $ y^2 = x(x+1)(x-2)^4\;$;
\item $y = x^2(x^2+1)(x^2-2)^4\,$.
\end{questionparts}
\begin{align*}
&& y &= x(x+1)(x-2)^4 \\
\Rightarrow && y' &= (x+1)(x-2)^4+x(x-2)^4+4x(x+1)(x-2)^3 \\
&&&= (x-2)^3 \left ( (2x+1)(x-2)+4x(x+1) \right) \\
&&&= (x-2)^3 \left (2x^2-3x-2+4x^2+4x \right) \\
&&&=(x-2)^3(6x^2+x-2) \\
&&&=(x-2)^3(2x-1)(3x+2)
\end{align*}
Therefore there are stationary points at $(2,0), (\frac12, -\frac{625}{64}), (-\frac23, -\frac{4078}{81})$
$(0,2)$ is a minimum by considering the sign of $y'$ either side.
$ (-\frac23, \frac{2560}{729})$ is a minimum, since it's the first stationary point.
$ (\frac12, \frac{243}{64})$ is a maximum since you can't have consecutive minima and the second derivative is clearly non-zero.
\begin{center}
\begin{tikzpicture}
\def\a{-0.8};
\def\functionf(#1){(#1)*((#1)+1)*((#1)-2)^4};
\def\xl{-5};
\def\xu{5};
\def\yl{-15};
\def\yu{20};
% Calculate scaling factors to make the plot square
\pgfmathsetmacro{\xrange}{\xu-\xl}
\pgfmathsetmacro{\yrange}{\yu-\yl}
\pgfmathsetmacro{\xscale}{10/\xrange}
\pgfmathsetmacro{\yscale}{10/\yrange}
% Define the styles for the axes and grid
\tikzset{
axis/.style={very thick, ->},
grid/.style={thin, gray!30},
x=\xscale cm,
y=\yscale cm
}
% Define the bounding region with clip
\begin{scope}
% You can modify these values to change your plotting region
\clip (\xl,\yl) rectangle (\xu,\yu);
\draw[blue, smooth, thick, domain=-2:3, samples=101]
plot({\x}, {\functionf(\x)});
% \draw[red, smooth, thick, domain=1:2, samples=101]
% plot({\x}, {1+3-1});
% \draw[red, smooth, thick, domain=2:3, samples=101]
% plot({\x}, {4+6-1});
\node[blue, above, rotate=-87.5] at (-1.1, {\functionf(-1.1)}) {\tiny $y=x(x+1)(x-2)^4$};
\filldraw (2, 0) circle (1.5pt) node[below] {$2$};
\filldraw (-1, 0) circle (1.5pt) node[below] {$-1$};
\filldraw ({-2/3}, {\functionf(-2/3)}) circle (1.5pt) node[below] {$(-\frac23, -\frac{4078}{81})$};
\filldraw ({1/2}, {243/64}) circle (1.5pt) node[above] {$(\frac12,\frac{243}{64})$};
\end{scope}
% Set up axes
\draw[axis] (\xl,0) -- (\xu,0) node[right] {$x$};
\draw[axis] (0,\yl) -- (0,\yu) node[above] {$y$};
\end{tikzpicture}
\end{center}
\begin{questionparts}
\item $\,$
\begin{center}
\begin{tikzpicture}
\def\a{-0.8};
\def\functionf(#1){(#1)*((#1)+1)*((#1)-2)^4};
\def\xl{-5};
\def\xu{5};
\def\yl{-15};
\def\yu{20};
% Calculate scaling factors to make the plot square
\pgfmathsetmacro{\xrange}{\xu-\xl}
\pgfmathsetmacro{\yrange}{\yu-\yl}
\pgfmathsetmacro{\xscale}{10/\xrange}
\pgfmathsetmacro{\yscale}{10/\yrange}
% Define the styles for the axes and grid
\tikzset{
axis/.style={very thick, ->},
grid/.style={thin, gray!30},
x=\xscale cm,
y=\yscale cm
}
% Define the bounding region with clip
\begin{scope}
% You can modify these values to change your plotting region
\clip (\xl,\yl) rectangle (\xu,\yu);
\draw[blue, smooth, thick, domain=-2:-1, samples=101]
plot({\x}, {sqrt(\functionf(\x))});
\draw[blue, smooth, thick, domain=-2:-1, samples=101]
plot({\x}, {-sqrt(\functionf(\x))});
\draw[blue, smooth, thick, domain=0:\xu, samples=101]
plot({\x}, {sqrt(\functionf(\x))});
\draw[blue, smooth, thick, domain=0:\xu, samples=101]
plot({\x}, {-sqrt(\functionf(\x))});
% \draw[red, smooth, thick, domain=1:2, samples=101]
% plot({\x}, {1+3-1});
% \draw[red, smooth, thick, domain=2:3, samples=101]
% plot({\x}, {4+6-1});
\node[blue, above, rotate=-80.5] at (-1.5, {sqrt(\functionf(-1.5))}) {\tiny $y^2=x(x+1)(x-2)^4$};
\filldraw (2, 0) circle (1.5pt) node[below] {$2$};
\filldraw (-1, 0) circle (1.5pt) node[below] {$-1$};
% \filldraw ({-2/3}, {\functionf(-2/3)}) circle (1.5pt) node[below] {$(-\frac23, -\frac{4078}{81})$};
\filldraw ({1/2}, {sqrt(243/64)}) circle (1.5pt) node[above] {$(\frac12,\frac{9\sqrt{3}}{8})$};
\filldraw ({1/2}, {-sqrt(243/64)}) circle (1.5pt) node[below] {$(\frac12,-\frac{9\sqrt{3}}{8})$};
\end{scope}
% Set up axes
\draw[axis] (\xl,0) -- (\xu,0) node[right] {$x$};
\draw[axis] (0,\yl) -- (0,\yu) node[above] {$y$};
\end{tikzpicture}
\end{center}
\item $\,$
\begin{center}
\begin{tikzpicture}
\def\a{-0.8};
\def\functionf(#1){(#1)*((#1)+1)*((#1)-2)^4};
\def\xl{-5};
\def\xu{5};
\def\yl{-15};
\def\yu{20};
% Calculate scaling factors to make the plot square
\pgfmathsetmacro{\xrange}{\xu-\xl}
\pgfmathsetmacro{\yrange}{\yu-\yl}
\pgfmathsetmacro{\xscale}{10/\xrange}
\pgfmathsetmacro{\yscale}{10/\yrange}
% Define the styles for the axes and grid
\tikzset{
axis/.style={very thick, ->},
grid/.style={thin, gray!30},
x=\xscale cm,
y=\yscale cm
}
% Define the bounding region with clip
\begin{scope}
% You can modify these values to change your plotting region
\clip (\xl,\yl) rectangle (\xu,\yu);
\draw[blue, smooth, thick, domain=-2:2, samples=101]
plot({\x}, {\functionf(\x*\x)});
% \draw[red, smooth, thick, domain=1:2, samples=101]
% plot({\x}, {1+3-1});
% \draw[red, smooth, thick, domain=2:3, samples=101]
% plot({\x}, {4+6-1});
\node[blue, above, rotate=-85] at (-1.65, {\functionf(1.73*1.73))}) {\tiny $y=x^2(x^2+1)(x^2-2)^4$};
\filldraw ({sqrt(2)}, 0) circle (1.5pt) node[below] {\tiny $\sqrt{2}$};
\filldraw ({-sqrt(2)}, 0) circle (1.5pt) node[below] {\tiny $-\sqrt{2}$};
% \filldraw (-1, 0) circle (1.5pt) node[below] {$-1$};
% \filldraw ({-2/3}, {\functionf(-2/3)}) circle (1.5pt) node[below] {$(-\frac23, -\frac{4078}{81})$};
\filldraw ({1/sqrt(2)}, {243/64}) circle (1.5pt) node[above] {\tiny $(\frac1{\sqrt{2}},\frac{243}{64})$};
\filldraw ({-1/sqrt(2)}, {243/64}) circle (1.5pt) node[above] {\tiny $(-\frac1{\sqrt{2}},\frac{243}{64})$};
\end{scope}
% Set up axes
\draw[axis] (\xl,0) -- (\xu,0) node[right] {$x$};
\draw[axis] (0,\yl) -- (0,\yu) node[above] {$y$};
\end{tikzpicture}
\end{center}
\end{questionparts}