2003 Paper 2 Q4

Year: 2003
Paper: 2
Question Number: 4

Course: LFM Pure
Section: Coordinate Geometry

Difficulty: 1600.0 Banger: 1484.0

Problem

The line \(y=d\,\), where \(d>0\,\), intersects the circle \(x^2+y^2=R^2\) at \(G\) and \(H\). Show that the area of the minor segment \(GH\) is equal to \begin{equation} R^2\arccos \left({d \over R}\right) -d\sqrt{R^2 - d^2}\;. \tag {\(*\)} \end{equation} In the following cases, the given line intersects the given circle. Determine how, in each case, the expression \((*)\) should be modified to give the area of the minor segment.
  1. Line: \(y=c\,\); \ \ \ circle: \((x-a)^2+(y-b)^2=R^2\,\).
  2. Line: \(y=mx+c\, \); \ \ \ circle: \(x^2+y^2=R^2\,\).
  3. Line: \(y=mx+c\,\); \ \ \ circle: \((x-a)^2+(y-b)^2=R^2\,\).

No solution available for this problem.

Rating Information

Difficulty Rating: 1600.0

Difficulty Comparisons: 0

Banger Rating: 1484.0

Banger Comparisons: 1

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Problem source
The line $y=d\,$, where $d>0\,$,
intersects the circle $x^2+y^2=R^2$ at $G$ and $H$. Show
that the area of the minor segment $GH$ is equal to
\begin{equation}
R^2\arccos \left({d \over R}\right) -d\sqrt{R^2 - d^2}\;.
\tag
{$*$}
\end{equation}

In the following cases, the given line intersects the
given circle. Determine how, in each case, the expression $(*)$ should be modified
to give the area of the minor
segment.

  
\begin{questionparts}
\item
Line: $y=c\,$; \ \ \ circle: $(x-a)^2+(y-b)^2=R^2\,$. 
\item
Line: $y=mx+c\, $;  \ \ \  circle: $x^2+y^2=R^2\,$. 

\item
Line: $y=mx+c\,$; \ \ \ circle: $(x-a)^2+(y-b)^2=R^2\,$.
\end{questionparts}