Year: 2003
Paper: 2
Question Number: 4
Course: LFM Pure
Section: Coordinate Geometry
No solution available for this problem.
Difficulty Rating: 1600.0
Difficulty Comparisons: 0
Banger Rating: 1484.0
Banger Comparisons: 1
The line $y=d\,$, where $d>0\,$,
intersects the circle $x^2+y^2=R^2$ at $G$ and $H$. Show
that the area of the minor segment $GH$ is equal to
\begin{equation}
R^2\arccos \left({d \over R}\right) -d\sqrt{R^2 - d^2}\;.
\tag
{$*$}
\end{equation}
In the following cases, the given line intersects the
given circle. Determine how, in each case, the expression $(*)$ should be modified
to give the area of the minor
segment.
\begin{questionparts}
\item
Line: $y=c\,$; \ \ \ circle: $(x-a)^2+(y-b)^2=R^2\,$.
\item
Line: $y=mx+c\, $; \ \ \ circle: $x^2+y^2=R^2\,$.
\item
Line: $y=mx+c\,$; \ \ \ circle: $(x-a)^2+(y-b)^2=R^2\,$.
\end{questionparts}