2002 Paper 2 Q6

Year: 2002
Paper: 2
Question Number: 6

Course: LFM Pure
Section: Trigonometry 2

Difficulty: 1600.0 Banger: 1484.0

Problem

The lines \(l_1\), \(l_2\) and \(l_3\) lie in an inclined plane \(P\) and pass through a common point \(A\). The line \(l_2\) is a line of greatest slope in \(P\). The line \(l_1\) is perpendicular to \(l_3\) and makes an acute angle \(\alpha\) with \(l_2\). The angles between the horizontal and \(l_1\), \(l_2\) and \(l_3\) are \(\pi/6\), \(\beta\) and \(\pi/4\), respectively. Show that \(\cos\alpha\sin\beta = \frac12\,\) and find the value of \(\sin\alpha \sin\beta\,\). Deduce that \(\beta = \pi/3\,\). The lines \(l_1\) and \(l_3\) are rotated in \(P\) about \(A\) so that \(l_1\) and \(l_3\) remain perpendicular to each other. The new acute angle between \(l_1\) and \(l_2\) is \(\theta\). The new angles which \(l_1\) and \(l_3\) make with the horizontal are \(\phi\) and \(2\phi\), respectively. Show that \[ \tan^2\theta = \frac{3+\sqrt{13}}2\;. \]

No solution available for this problem.

Rating Information

Difficulty Rating: 1600.0

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Banger Rating: 1484.0

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Problem source
The lines $l_1$, $l_2$ and $l_3$ lie in an inclined plane $P$ and    pass through 
a common point $A$.  The line $l_2$ is a
line of greatest slope in $P$.  The line $l_1$ is  perpendicular to $l_3$ and
makes an acute angle $\alpha$ with $l_2$.
The angles between the horizontal and 
$l_1$, $l_2$  and $l_3$ are  $\pi/6$, $\beta$  and $\pi/4$, respectively. 
Show that $\cos\alpha\sin\beta = \frac12\,$
and find the value of $\sin\alpha \sin\beta\,$. Deduce that 
$\beta = \pi/3\,$.
The lines $l_1$ and $l_3$ are rotated in $P$ about 
$A$ so that $l_1$ and $l_3$ remain perpendicular to each other.
The new acute angle between
$l_1$ and $l_2$ is $\theta$.  The new angles which $l_1$ and $l_3$
 make with the horizontal are $\phi$ and $2\phi$, respectively.  Show that
\[
             \tan^2\theta = \frac{3+\sqrt{13}}2\;.
\]