2002 Paper 1 Q11

Year: 2002
Paper: 1
Question Number: 11

Course: UFM Mechanics
Section: Momentum and Collisions 2

Difficulty: 1500.0 Banger: 1484.0

Problem

\(\,\)
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A particle \(P_1\) of mass \(m\) collides with a particle \(P_2\) of mass \(km\) which is at rest. No energy is lost in the collision. The direction of motion of \(P_1\) and \(P_2\) after the collision make non-zero angles of \(\theta\) and \(\phi\), respectively, with the direction of motion of \(P_1\) before the collision, as shown. Show that \[ \sin^2\theta + k\sin^2\phi = k\sin^2(\theta+\phi) \;. \] Show that, if the angle between the particles after the collision is a right angle, then \(k=1\,\).

No solution available for this problem.

Rating Information

Difficulty Rating: 1500.0

Difficulty Comparisons: 0

Banger Rating: 1484.0

Banger Comparisons: 1

Show LaTeX source
Problem source
$\,$
	
\begin{center}
\psset{xunit=1.0cm,yunit=1.0cm,algebraic=true,dimen=middle,dotstyle=o,dotsize=3pt 0,linewidth=0.5pt,arrowsize=3pt 2,arrowinset=0.25}
\begin{pspicture*}(-2.62,-2.1)(6.82,1.68)
\psline{->}(-1.7,0)(-0.22,0)
\psline[linestyle=dashed,dash=1pt 1pt](3,0)(6,0)
\psline{->}(4,0)(5.38,0.88)
\psline{->}(4,0)(5,-1)
\rput[tl](-2.36,0.71){$P_1$}
\rput[tl](0.54,0.71){$P_2$}
\rput[tl](-2.51,-0.16){$m$}
\rput[tl](0.61,-0.16){$km$}
\rput[tl](4.59,0.34){$\theta$}
\rput[tl](4.53,-0.08){$\phi$}
\rput[tl](5.87,1.55){$P_1$}
\rput[tl](5.33,-1.17){$P_2$}
\begin{scriptsize}
\psdots[dotsize=5pt 0,dotstyle=*](-2,0)
\psdots[dotsize=5pt 0,dotstyle=*](0.46,0)
\psdots[dotsize=5pt 0,dotstyle=*](5.62,1)
\psdots[dotsize=5pt 0,dotstyle=*](5.13,-1.18)
\end{scriptsize}
\end{pspicture*}
\end{center}
A particle $P_1$ of mass $m$ collides with  a particle $P_2$
of mass $km$ which is at rest. No energy is lost in the collision.
 The direction of motion 
of $P_1$ and $P_2$ after the collision make 
non-zero
angles of  $\theta$ and $\phi$, respectively, with the direction of motion 
of $P_1$ before the collision, as shown. Show that
\[
\sin^2\theta + k\sin^2\phi = k\sin^2(\theta+\phi) \;.
\] 
Show that, if the angle between the particles after the collision is a right angle,
then $k=1\,$.