2000 Paper 1 Q10

Year: 2000
Paper: 1
Question Number: 10

Course: UFM Mechanics
Section: Momentum and Collisions 1

Difficulty: 1516.0 Banger: 1500.0

Problem

Three particles \(P_1\), \(P_2\) and \(P_3\) of masses \(m_{1}\), \(m_{2}\) and \(m_{3}\) respectively lie at rest in a straight line on a smooth horizontal table. \(P_1\) is projected with speed \(v\) towards \(P_2\) and brought to rest by the collision. After \(P_2\) collides with \(P_3\), the latter moves forward with speed \(v\). The coefficients of restitution in the first and second collisions are \(e\) and \(e'\), respectively. Show that \[ e'= \frac{m_{2}+m_{3}-m_{1}}{m_{1}}. \] Show that \(2m_1\ge m_2 +m_3\ge m_1\) for such collisions to be possible. If \(m_1\), \(m_3\) and \(v\) are fixed, find, in terms of \(m_1\), \(m_3\) and \(v\), the largest and smallest possible values for the final energy of the system.

No solution available for this problem.

Rating Information

Difficulty Rating: 1516.0

Difficulty Comparisons: 1

Banger Rating: 1500.0

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Problem source
Three particles $P_1$, $P_2$ and $P_3$
of masses $m_{1}$, $m_{2}$ and  $m_{3}$ respectively 
lie at rest in a straight line on a smooth horizontal table. 
$P_1$ is projected with speed $v$ 
towards $P_2$ and brought to rest by the collision. 
After $P_2$  collides with $P_3$, 
the latter moves forward with speed $v$. The coefficients of restitution
in the first and second collisions are $e$ and $e'$, respectively.
Show that 
\[
e'=
\frac{m_{2}+m_{3}-m_{1}}{m_{1}}.
\] 
 
Show that 
$2m_1\ge m_2 +m_3\ge m_1$
for such collisions to be possible.
If $m_1$,  $m_3$ and $v$ are fixed, find,  in terms of $m_1$, $m_3$ and 
$v$,
the largest and smallest possible
values for the final  energy of the system.