1998 Paper 1 Q8

Year: 1998
Paper: 1
Question Number: 8

Course: LFM Pure
Section: Differential equations

Difficulty: 1516.0 Banger: 1500.0

Problem

Fluid flows steadily under a constant pressure gradient along a straight tube of circular cross-section of radius \(a\). The velocity \(v\) of a particle of the fluid is parallel to the axis of the tube and depends only on the distance \(r\) from the axis. The equation satisfied by \(v\) is \[\frac{1}{r}\frac{{\mathrm d}\ }{{\mathrm d}r} \left(r\frac{{\mathrm d}v}{{\mathrm d}r}\right) =-k,\] where \(k\) is constant. Find the general solution for \(v\). Show that \(|v|\rightarrow\infty\) as \(r\rightarrow 0\) unless one of the constants in your solution is chosen to be~\(0\). Suppose that this constant is, in fact, \(0\) and that \(v=0\) when \(r=a\). Find \(v\) in terms of \(k\), \(a\) and \(r\). The volume \(F\) flowing through the tube per unit time is given by \[F=2\pi\int_{0}^{a}rv\,{\mathrm d}r. \] Find \(F\).

No solution available for this problem.

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Difficulty Rating: 1516.0

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Banger Rating: 1500.0

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Problem source
Fluid flows steadily under a constant pressure
gradient along a straight tube of circular 
cross-section of radius $a$. The velocity $v$
of a particle of the fluid is parallel to the axis of the tube 
and depends only on the distance $r$
from the axis. The equation satisfied by $v$ is
\[\frac{1}{r}\frac{{\mathrm d}\ }{{\mathrm d}r}
\left(r\frac{{\mathrm d}v}{{\mathrm d}r}\right)
=-k,\]
where $k$ is constant. 
Find the general solution for $v$. 
Show that $|v|\rightarrow\infty$ as $r\rightarrow 0$ 
unless one of the constants in your solution 
is chosen to be~$0$.
Suppose that this constant is, in fact, $0$ and
that $v=0$ when $r=a$.
Find $v$ in terms of $k$, $a$ and $r$. 
The volume $F$ flowing through the tube
per unit time is given by
\[F=2\pi\int_{0}^{a}rv\,{\mathrm d}r.
\]
Find $F$.