1997 Paper 3 Q7

Year: 1997
Paper: 3
Question Number: 7

Course: UFM Pure
Section: Sequences and series, recurrence and convergence

Difficulty: 1700.0 Banger: 1516.0

Problem

For each positive integer \(n\), let \begin{align*} a_n&=\frac1{n+1}+\frac1{(n+1)(n+2)}+\frac1{(n+1)(n+2)(n+3)}+\cdots;\\ b_n&=\frac1{n+1}+\frac1{(n+1)^2}+\frac1{(n+1)^3}+\cdots. \end{align*}
  1. Evaluate \(b_n\).
  2. Show that \(0
  3. Deduce that \(a_n=n!{\rm e}-[n!{\rm e}]\) (where \([x]\) is the integer part of \(x\)).
  4. Hence show that \(\mathrm{e}\) is irrational.

No solution available for this problem.

Rating Information

Difficulty Rating: 1700.0

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Banger Rating: 1516.0

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Show LaTeX source
Problem source
For each positive integer $n$,
let
\begin{align*}
a_n&=\frac1{n+1}+\frac1{(n+1)(n+2)}+\frac1{(n+1)(n+2)(n+3)}+\cdots;\\
b_n&=\frac1{n+1}+\frac1{(n+1)^2}+\frac1{(n+1)^3}+\cdots.
\end{align*}
\begin{questionparts}
\item Evaluate $b_n$.
\item Show that $0<a_n<1/n$.
\item Deduce that $a_n=n!{\rm e}-[n!{\rm e}]$ (where $[x]$ is
the integer part of $x$).
\item Hence show that $\mathrm{e}$ is irrational.
\end{questionparts}