Year: 1996
Paper: 3
Question Number: 8
Course: LFM Pure
Section: Simultaneous equations
No solution available for this problem.
Difficulty Rating: 1700.0
Difficulty Comparisons: 0
Banger Rating: 1516.0
Banger Comparisons: 1
A transformation $T$ of the real numbers is defined by
\[
y=T(x)=\frac{ax-b}{cx-d}\,,
\]
where $a,b,c$, $d$ are real numbers such that $ad\neq bc$. Find
all numbers $x$ such that $T(x)=x.$ Show that the inverse operation,
$x=T^{-1}(y)$ expressing $x$ in terms of $y$ is of the same form
as $T$ and find corresponding numbers $a',b',c'$,$d'$.
Let $S_{r}$ denote the set of all real numbers excluding $r$. Show
that, if $c\neq0,$ there is a value of $r$ such that $T$ is defined
for all $x\in S_{r}$ and find the image $T(S_{r}).$ What is the
corresponding result if $c=0$?
If $T_{1},$ given by numbers $a_{1},b_{1},c_{1},d_{1},$ and $T_{2},$
given by numbers $a_{2},b_{2},c_{2},d_{2}$ are two such transformations,
show that their composition $T_{3},$ defined by $T_{3}(x)=T_{2}(T_{1}(x)),$
is of the same form.
Find necessary and sufficient conditions on the numbers $a,b,c,d$
for $T^{2}$, the composition of $T$ with itself, to be the identity.
Hence, or otherwise, find transformations $T_{1},T_{2}$ and their
composition $T_{3}$ such that $T_{1}^{2}$ and $T_{2}^{2}$ are each
the identity but $T_{3}^{2}$ is not.