1994 Paper 2 Q7

Year: 1994
Paper: 2
Question Number: 7

Course: LFM Pure
Section: Coordinate Geometry

Difficulty: 1600.0 Banger: 1500.0

Problem

Show that the equation \[ ax^{2}+ay^{2}+2gx+2fy+c=0 \] where \(a>0\) and \(f^{2}+g^{2}>ac\) represents a circle in Cartesian coordinates and find its centre. The smooth and level parade ground of the First Ruritanian Infantry Division is ornamented by two tall vertical flagpoles of heights \(h_{1}\) and \(h_{2}\) a distance \(d\) apart. As part of an initiative test a soldier has to march in such a way that he keeps the angles of elevation of the tops of the two flagpoles equal to one another. Show that if the two flagpoles are of different heights he will march in a circle. What happens if the two flagpoles have the same height? To celebrate the King's birthday a third flagpole is added. Soldiers are then assigned to each of the three different pairs of flagpoles and are told to march in such a way that they always keep the tops of their two assigned flagpoles at equal angles of elevation to one another. Show that, if the three flagpoles have different heights \(h_{1},h_{2}\) and \(h_{3}\) and the circles in which the soldiers march have centres of \((x_{ij},y_{ij})\) (for the flagpoles of height \(h_{i}\) and \(h_{j}\)) relative to Cartesian coordinates fixed in the parade ground, then the \(x_{ij}\) satisfy \[ h_{3}^{2}\left(h_{1}^{2}-h_{2}^{2}\right)x_{12}+h_{1}^{2}\left(h_{2}^{2}-h_{3}^{2}\right)x_{23}+h_{2}^{2}\left(h_{3}^{2}-h_{1}^{2}\right)x_{31}=0, \] and the same equation connects the \(y_{ij}\). Deduce that the three centres lie in a straight line.

No solution available for this problem.

Rating Information

Difficulty Rating: 1600.0

Difficulty Comparisons: 0

Banger Rating: 1500.0

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Problem source
Show that the equation 
\[
ax^{2}+ay^{2}+2gx+2fy+c=0
\]
where $a>0$ and $f^{2}+g^{2}>ac$ represents a circle in Cartesian
coordinates and find its centre. 

The smooth and level parade ground of the First Ruritanian Infantry
Division is ornamented by two tall vertical flagpoles of heights $h_{1}$
and $h_{2}$ a distance $d$ apart. As part of an initiative test
a soldier has to march in such a way that he keeps the angles of elevation
of the tops of the two flagpoles equal to one another. Show that if
the two flagpoles are of different heights he will march in a circle.
What happens if the two flagpoles have the same height?

To celebrate the King's birthday a third flagpole is added. Soldiers
are then assigned to each of the three different pairs of flagpoles
and are told to march in such a way that they always keep the tops
of their two assigned flagpoles at equal angles of elevation to one
another. Show that, if the three flagpoles have different heights
$h_{1},h_{2}$ and $h_{3}$ and the circles in which the soldiers
march have centres of $(x_{ij},y_{ij})$ (for the flagpoles of height
$h_{i}$ and $h_{j}$) relative to Cartesian coordinates fixed in
the parade ground, then the $x_{ij}$ satisfy 
\[
h_{3}^{2}\left(h_{1}^{2}-h_{2}^{2}\right)x_{12}+h_{1}^{2}\left(h_{2}^{2}-h_{3}^{2}\right)x_{23}+h_{2}^{2}\left(h_{3}^{2}-h_{1}^{2}\right)x_{31}=0,
\]
and the same equation connects the $y_{ij}$. Deduce that the three
centres lie in a straight line.