Year: 1994
Paper: 1
Question Number: 5
Course: UFM Pure
Section: Conic sections
Difficulty Rating: 1500.0
Difficulty Comparisons: 0
Banger Rating: 1516.0
Banger Comparisons: 1
A parabola has the equation $y=x^{2}.$ The points $P$ and $Q$ with coordinates $(p,p^{2})$ and $(q,q^{2})$ respectively move on the parabola in such a way that $\angle POQ$ is always a right angle.
\begin{questionparts}
\item Find and sketch the locus of the midpoint $R$ of the chord $PQ.$
\item Find and sketch the locus of the point $T$ where the tangents to the parabola at $P$ and $Q$ intersect.
\end{questionparts}
\begin{questionparts}
\item The line $PO$ has gradient $\frac{p^2}{p} = p$ and teh line $QO$ has gradient $q$, therefore we must have that $pq = -1$. Therefore, $R$ is the point
\begin{align*}
&& R &= \left ( \frac{p-\frac{1}{p}}{2}, \frac{p^2+\frac{1}{p^2}}{2} \right) \\
&&&= \left ( \frac12\left ( p - \frac{1}{p} \right),2\left (\frac12 \left(p-\frac{1}{p}\right) \right)^2+1 \right) \\
&&&= \left ( t, 2t^2+1\right)
\end{align*}
So we are looking at another parabola.
\begin{center}
\begin{tikzpicture}
\def\functionf(#1){1/cos(#1*180/pi)};
\def\xl{-3};
\def\xu{3};
\def\yl{-0.5};
\def\yu{5.2};
% Calculate scaling factors to make the plot square
\pgfmathsetmacro{\xrange}{\xu-\xl}
\pgfmathsetmacro{\yrange}{\yu-\yl}
\pgfmathsetmacro{\xscale}{10/\xrange}
\pgfmathsetmacro{\yscale}{10/\yrange}
% Define the styles for the axes and grid
\tikzset{
axis/.style={very thick, ->},
grid/.style={thin, gray!30},
x=\xscale cm,
y=\yscale cm
}
% Define the bounding region with clip
\begin{scope}
% You can modify these values to change your plotting region
\clip (\xl,\yl) rectangle (\xu,\yu);
% Draw a grid (optional)
% \draw[grid] (-5,-3) grid (5,3);
\draw[thick, blue, smooth, domain=\xl:\xu, samples=100]
plot (\x, {\x*\x});
\draw[thick, red, smooth, domain=\xl:\xu, samples=100]
plot (\x, {2*\x*\x+1});
\node[below left] at ({pi},0) {$\pi$};
\draw (1,1) -- (-1,1);
\filldraw (0,1) circle (1pt);
\draw(2,4) -- (-0.5, 0.25);
\filldraw ({(2-0.5)/2},{(4+0.25)*0.5}) circle (1pt);
\end{scope}
% Set up axes
\draw[axis] (\xl,0) -- (\xu,0) node[right] {$x$};
\draw[axis] (0,\yl) -- (0,\yu) node[above] {$y$};
\end{tikzpicture}
\end{center}
\item The tangents are $y = 2px+c$, ie $p^2 = 2p^2+c$, ie $y = 2px -p^2$ so we have
\begin{align*}
&& y - 2px &= -p^2 \\
&& y - 2qx &= -q^2 \\
\Rightarrow && (2p-2q)x &= p^2-q^2 \\
\Rightarrow && x &= \frac12 (p+q)\\
&& y &= p(p+q)-p^2 \\
&& y &= pq = -1
\end{align*}
Therefore $x = \frac12(p - \frac1p), y= -1$, so we have the line $y = -1$ (the directrix)
\begin{center}
\begin{tikzpicture}
\def\functionf(#1){1/cos(#1*180/pi)};
\def\xl{-3};
\def\xu{3};
\def\yl{-1.5};
\def\yu{5.2};
% Calculate scaling factors to make the plot square
\pgfmathsetmacro{\xrange}{\xu-\xl}
\pgfmathsetmacro{\yrange}{\yu-\yl}
\pgfmathsetmacro{\xscale}{10/\xrange}
\pgfmathsetmacro{\yscale}{10/\yrange}
% Define the styles for the axes and grid
\tikzset{
axis/.style={very thick, ->},
grid/.style={thin, gray!30},
x=\xscale cm,
y=\yscale cm
}
% Define the bounding region with clip
\begin{scope}
% You can modify these values to change your plotting region
\clip (\xl,\yl) rectangle (\xu,\yu);
% Draw a grid (optional)
% \draw[grid] (-5,-3) grid (5,3);
\draw[thick, blue, smooth, domain=\xl:\xu, samples=100]
plot (\x, {\x*\x});
\draw[thick, red, smooth, domain=\xl:\xu, samples=100]
plot (\x, {2*\x*\x+1});
% \draw (1,1) -- (-1,1);
\draw (\xl, {2*\xl-1})--(\xu, {2*\xu-1});
\draw (\xl, {-2*\xl-1})--(\xu, {-2*\xu-1});
% \draw(2,4) -- (-0.5, 0.25);
\draw (\xl, {4*\xl-4})--(\xu, {4*\xu-4});
\draw (\xl, {-1*\xl-0.25})--(\xu, {-1*\xu-0.25});
% \filldraw ({(2-0.5)/2},{(4+0.25)*0.5}) circle (1pt);
\draw (\xl,-1) -- (\xu,-1);
\end{scope}
% Set up axes
\draw[axis] (\xl,0) -- (\xu,0) node[right] {$x$};
\draw[axis] (0,\yl) -- (0,\yu) node[above] {$y$};
\end{tikzpicture}
\end{center}
\end{questionparts}