1993 Paper 1 Q5

Year: 1993
Paper: 1
Question Number: 5

Course: LFM Stats And Pure
Section: Complex Numbers (L8th)

Difficulty: 1500.0 Banger: 1516.0

Problem

If \(z=x+\mathrm{i}y\) where \(x\) and \(y\) are real, define \(\left|z\right|\) in terms of \(x\) and \(y\). Show, using your definition, that if \(z_{1},z_{2}\in\mathbb{C}\) then \(\left|z_{1}z_{2}\right|=\left|z_{1}\right|\left|z_{2}\right|.\) Explain, by means of a diagram, or otherwise, why \(\left|z_{1}+z_{2}\right|\leqslant\left|z_{1}\right|+\left|z_{2}\right|.\) Suppose that \(a_{j}\in\mathbb{C}\) and \(\left|a_{j}\right|\leqslant1\) for \(j=1,2,\ldots,n.\) Show that, if \(\left|z\right|\leqslant\frac{1}{2},\) then \[ \left|a_{n}z^{n}+a_{n-1}z^{n-1}+\cdots+a_{1}z\right|<1, \] and deduce that any root \(w\) of the equation \[ a_{n}z^{n}+a_{n-1}z^{n-1}+\cdots+a_{1}z+1=0 \] must satisfy \(\left|x\right|>\frac{1}{2}.\)

No solution available for this problem.

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Difficulty Rating: 1500.0

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Banger Rating: 1516.0

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Problem source
If $z=x+\mathrm{i}y$ where $x$ and $y$ are real, define $\left|z\right|$
in terms of $x$ and $y$. Show, using your definition, that if $z_{1},z_{2}\in\mathbb{C}$
then $\left|z_{1}z_{2}\right|=\left|z_{1}\right|\left|z_{2}\right|.$ 
Explain, by means of a diagram, or otherwise, why $\left|z_{1}+z_{2}\right|\leqslant\left|z_{1}\right|+\left|z_{2}\right|.$ 

Suppose that $a_{j}\in\mathbb{C}$ and $\left|a_{j}\right|\leqslant1$
for $j=1,2,\ldots,n.$ Show that, if $\left|z\right|\leqslant\frac{1}{2},$
then 
\[
\left|a_{n}z^{n}+a_{n-1}z^{n-1}+\cdots+a_{1}z\right|<1,
\]
and deduce that any root $w$ of the equation 
\[
a_{n}z^{n}+a_{n-1}z^{n-1}+\cdots+a_{1}z+1=0
\]
must satisfy $\left|x\right|>\frac{1}{2}.$