Year: 1992
Paper: 1
Question Number: 8
Course: LFM Pure and Mechanics
Section: Integration as Area
No solution available for this problem.
Difficulty Rating: 1500.0
Difficulty Comparisons: 0
Banger Rating: 1500.0
Banger Comparisons: 0
Explain diagrammatically, or otherwise, why
\[
\frac{\mathrm{d}}{\mathrm{d}x}\int_{a}^{x}\mathrm{f}(t)\,\mathrm{d}t=\mathrm{f}(x).
\]
Show that, if
\[
\mathrm{f}(x)=\int_{0}^{x}\mathrm{f}(t)\,\mathrm{d}t+1,
\]
then $\mathrm{f}(x)=\mathrm{e}^{x}.$
What is the solution of
\[
\mathrm{f}(x)=\int_{0}^{x}\mathrm{f}(t)\,\mathrm{d}t?
\]
Given that
\[
\int_{0}^{x}\mathrm{f}(t)\,\mathrm{d}t=\int_{x}^{1}t^{2}\mathrm{f}(t)\,\mathrm{d}t+x-\frac{x^{5}}{5}+C,
\]
find $\mathrm{f}(x)$ and show that $C=-2/15.$