1988 Paper 1 Q1

Year: 1988
Paper: 1
Question Number: 1

Course: LFM Pure and Mechanics
Section: Exponentials and Logarithms

Difficulty: 1500.0 Banger: 1500.0

Problem

Sketch the graph of the function \(\mathrm{h}\), where \[ \mathrm{h}(x)=\frac{\ln x}{x},\qquad(x>0). \] Hence, or otherwise, find all pairs of distinct positive integers \(m\) and \(n\) which satisfy the equation \[ n^{m}=m^{n}. \]

Solution

TikZ diagram
If \(n^m = m^n \Rightarrow \frac{\ln m}{m} = \frac{\ln n}{n}\) so if \(n < m\) we must have that \(n < e \Rightarrow n = 1,2\). \(n = 1\) has no solutions, so consider \(n = 2\) which obviously has the corresponding solution \(m=4\). Since \(h(x)\) is decreasing for \(x > e\) we know this is the only solution. Hence the only solution for distinct \(m,n\) are \((m,n) = (2,4), (4,2)\)
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Difficulty Rating: 1500.0

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Banger Rating: 1500.0

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Show LaTeX source
Problem source
Sketch the graph of the function $\mathrm{h}$, where 
\[
\mathrm{h}(x)=\frac{\ln x}{x},\qquad(x>0).
\]
Hence, or otherwise, find all pairs of distinct positive integers
$m$ and $n$ which satisfy the equation 
\[
n^{m}=m^{n}.
\]
Solution source
\begin{center}
\begin{tikzpicture}[scale=2]
    \draw[->] (-.1, 0) -- (3, 0);
    \draw[->] (0,-1) -- (0,1);

    \node at (3,0) [right] {$x$};
    \node at (0,1) [above] {$y$};
    \node at (3.5,0.2) [above] {$y = \frac{\ln x}{x}$};
    \node at ({exp(1)/5},{2/exp(1)}) [above] {$(e, \frac1{e})$};
    \node at ({1/5},0) [below, right] {$(1,0)$};
    \draw[domain = 0.75:15, samples=180, variable = \x]  plot ({\x/5},{2*ln(\x)/\x}); 
\end{tikzpicture}
\end{center}

If $n^m = m^n \Rightarrow \frac{\ln m}{m} = \frac{\ln n}{n}$ so if $n < m$ we must have that $n < e \Rightarrow n = 1,2$. $n = 1$ has no solutions, so consider $n = 2$ which obviously has the corresponding solution $m=4$. Since $h(x)$ is decreasing for $x > e$ we know this is the only solution. Hence the only solution for distinct $m,n$ are $(m,n) = (2,4), (4,2)$