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2014 Paper 3 Q9
D: 1700.0 B: 1500.0

A particle of mass \(m\) is projected with velocity \(\+ u\). It is acted upon by the force \(m\+g\) due to gravity and by a resistive force \(-mk \+v\), where \(\+v\) is its velocity and \(k\) is a positive constant. Given that, at time \(t\) after projection, its position \(\+r\) relative to the point of projection is given by \[ \+r = \frac{kt -1 +\.e^{-kt}} {k^2} \, \+g + \frac{ 1-\.e^{-kt}}{k} \, \+u \,, \] find an expression for \(\+v\) in terms of \(k\), \(t\), \(\+g\) and \(\+u\). Verify that the equation of motion and the initial conditions are satisfied. Let \(\+u = u\cos\alpha \, \+i + u \sin\alpha \, \+j\) and $\+g = -g\, \+j\(, where \)0<\alpha<90^\circ\(, and let \)T$ be the time after projection at which \(\+r \,.\, \+j =0\). Show that \[ uk \sin\alpha = \left(\frac{kT}{1-\.e^{-kT}} -1\right)g\,. \] Let \(\beta\) be the acute angle between \(\+v\) and \(\+i\) at time \(T\). Show that \[ \tan\beta = \frac{(\.e^{kT}-1)g}{uk\cos\alpha}-\tan\alpha \,. \] Show further that \(\tan\beta >\tan\alpha\) (you may assume that \(\sinh kT >kT\)) and deduce that~\(\beta >\alpha\).

2013 Paper 2 Q9
D: 1600.0 B: 1485.6

The diagram shows three identical discs in equilibrium in a vertical plane. Two discs rest, not in contact with each other, on a horizontal surface and the third disc rests on the other two. The angle at the upper vertex of the triangle joining the centres of the discs is \(2\theta\).

\psset{xunit=0.7cm,yunit=0.7cm,algebraic=true,dimen=middle,dotstyle=o,dotsize=3pt 0,linewidth=0.3pt,arrowsize=3pt 2,arrowinset=0.25} \begin{pspicture*}(-7,-0.42)(7,6.86) \psline(-7,0)(7,0) \pscircle(-3,2){1.4} \pscircle(3,2){1.4} \pscircle(0,4.64){1.4} \psline(0,4.64)(-3,2) \psline(0,4.64)(3,2) \psline(0,4.64)(0,0.9) \parametricplot{-1.5707963267948966}{-0.722030440522891}{1*cos(t)+0|1*sin(t)+4.64} \rput[tl](0.16,4.25){\(\theta\)} \end{pspicture*}
\noindent The weight of each disc is \(W\). The coefficient of friction between a disc and the horizontal surface is \(\mu\) and the coefficient of friction between the discs is also \(\mu\).
  1. Show that the normal reaction between the horizontal surface and a disc in contact with the surface is \(\frac32 W\,\).
  2. Find the normal reaction between two discs in contact and show that the magnitude of the frictional force between two discs in contact is \(\dfrac{W\sin\theta}{2(1+\cos\theta)}\,\).
  3. Show that if \(\mu <2- \surd3\,\) there is no value of \(\theta\) for which equilibrium is possible.

2003 Paper 1 Q4
D: 1500.0 B: 1500.0

Solve the inequality $$\frac{\sin\theta+1}{\cos\theta}\le1\;$$ where \(0\le\theta<2\pi\,\) and \(\cos\theta\ne0\,\).


Solution:

TikZ diagram
\(\theta \in \{0\} \cup (\frac{\pi}{2}, 2\pi]\). In \((0, \frac{\pi}{2})\) \(\cos \theta < 1 + \sin \theta\), and then it's either negative or greater than \(1+ \sin \theta\)