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2013 Paper 2 Q9
D: 1600.0 B: 1485.6

The diagram shows three identical discs in equilibrium in a vertical plane. Two discs rest, not in contact with each other, on a horizontal surface and the third disc rests on the other two. The angle at the upper vertex of the triangle joining the centres of the discs is \(2\theta\).

\psset{xunit=0.7cm,yunit=0.7cm,algebraic=true,dimen=middle,dotstyle=o,dotsize=3pt 0,linewidth=0.3pt,arrowsize=3pt 2,arrowinset=0.25} \begin{pspicture*}(-7,-0.42)(7,6.86) \psline(-7,0)(7,0) \pscircle(-3,2){1.4} \pscircle(3,2){1.4} \pscircle(0,4.64){1.4} \psline(0,4.64)(-3,2) \psline(0,4.64)(3,2) \psline(0,4.64)(0,0.9) \parametricplot{-1.5707963267948966}{-0.722030440522891}{1*cos(t)+0|1*sin(t)+4.64} \rput[tl](0.16,4.25){\(\theta\)} \end{pspicture*}
\noindent The weight of each disc is \(W\). The coefficient of friction between a disc and the horizontal surface is \(\mu\) and the coefficient of friction between the discs is also \(\mu\).
  1. Show that the normal reaction between the horizontal surface and a disc in contact with the surface is \(\frac32 W\,\).
  2. Find the normal reaction between two discs in contact and show that the magnitude of the frictional force between two discs in contact is \(\dfrac{W\sin\theta}{2(1+\cos\theta)}\,\).
  3. Show that if \(\mu <2- \surd3\,\) there is no value of \(\theta\) for which equilibrium is possible.