A smooth hemispherical bowl of mass \(2m\) is rigidly mounted on a
light carriage which slides freely on a horizontal table as shown
in the diagram. The rim of the bowl is horizontal and has centre \(O\).
A particle \(P\) of mass \(m\) is free to slide on the inner surface
of the bowl. Initially, \(P\) is in contact with the rim of the bowl
and the system is at rest. The system is released and when \(OP\) makes
an angle \(\theta\) with the horizontal the velocity of the bowl is
\(v\)? Show that
\[3v=a\dot{\theta}\sin\theta
\]
and that
\[
v^{2}=\frac{2ga\sin^{3}\theta}{3(3-\sin^{2}\theta)},
\]
where \(a\) is the interior radius of the bowl.
Find, in terms of \(m,g\) and \(\theta,\) the reaction between the bowl
and the particle.