2010 Paper 3 Q11

Year: 2010
Paper: 3
Question Number: 11

Course: UFM Mechanics
Section: Momentum and Collisions 1

Difficulty: 1700.0 Banger: 1469.5

Problem

A bullet of mass \(m\) is fired horizontally with speed \(u\) into a wooden block of mass \(M\) at rest on a horizontal surface. The coefficient of friction between the block and the surface is \(\mu\). While the bullet is moving through the block, it experiences a constant force of resistance to its motion of magnitude \(R\), where \(R>(M+m)\mu g\). The bullet moves horizontally in the block and does not emerge from the other side of the block.
  1. Show that the magnitude, \(a\), of the deceleration of the bullet relative to the block while the bullet is moving through the block is given by \[ a= \frac R m + \frac {R-(M+m)\mu g}{M}\, . \]
  2. Show that the common speed, \(v\), of the block and bullet when the bullet stops moving through the block satisfies \[ av = \frac{Ru-(M+m)\mu gu}M\,. \]
  3. Obtain an expression, in terms of \(u\), \(v\) and \(a\), for the distance moved by the block while the bullet is moving through the block.
  4. Show that the total distance moved by the block is \[ \frac{muv}{2(M+m)\mu g}\,. \]
Describe briefly what happens if \(R< (M+m)\mu g\).

No solution available for this problem.

Examiner's report
— 2010 STEP 3, Question 11
Mean: ~4 / 20 (inferred) ~16% attempted (inferred) Inferred ~4/20: 'least well scored upon of any on the paper'; must be below Q6 (~5). Inferred ~16% from 'slightly fewer than Q9' (~18%).

Slightly fewer attempted this than question 9, and this question was least well scored upon of any on the paper. Generally, candidates got through part (i) successfully and then either gave up or got right through the question. Common errors were the misapplication of conservation of momentum, failure to distinguish directions which led to negative signs which were then mis-handled to obtain the quoted answer in (i), and even strong candidates failing to appreciate that acceleration was constant making the later parts all susceptible to constant acceleration formulae and thus not requiring less direct approaches. The brief description at the end was usually restricted to only trivially considering the block, and few gave any thought to the bullet.

About 80% of candidates attempted at least five questions, and well less than 20% made genuine attempts at more than six. Those attempting more than six questions fell into three camps which were those weak candidates who made very little progress on any question, those with four or five fair solutions casting about for a sixth, and those strong candidates that either attempted 7th or even 8th questions as an "insurance policy" against a solution that seemed strong but wasn't, or else for entertainment!

Source: Cambridge STEP 2010 Examiner's Report · 2010-full.pdf
Rating Information

Difficulty Rating: 1700.0

Difficulty Comparisons: 0

Banger Rating: 1469.5

Banger Comparisons: 2

Show LaTeX source
Problem source
A bullet of mass $m$ is fired horizontally with speed $u$ into a 
wooden block of
mass $M$ at rest on a horizontal surface. The coefficient of friction
between the block and the surface is $\mu$. While
the bullet is moving through the block, it 
experiences a constant force of resistance to its motion
of magnitude $R$, where $R>(M+m)\mu g$.
The bullet moves horizontally in the block and does not emerge from the
other side of the block.
 
\begin{questionparts}
\item
Show that 
the magnitude, $a$, of the deceleration
of the bullet relative to the block
while the bullet is moving through the block is given by
\[
a= 
\frac R m + \frac {R-(M+m)\mu g}{M}\,
.
\]
\item Show that the common speed, $v$,  of the block and bullet when the 
bullet stops moving through the block satisfies
\[
av = \frac{Ru-(M+m)\mu gu}M\,.
\]
\item Obtain an expression, in terms of $u$, $v$ and $a$, for the 
distance moved by the block while the bullet is moving through the block.
\item Show that the total distance moved by the block is 
\[
\frac{muv}{2(M+m)\mu g}\,.
\]
\end{questionparts}
Describe briefly what happens if $R< (M+m)\mu g$.