1988 Paper 3 Q11

Year: 1988
Paper: 3
Question Number: 11

Course: UFM Mechanics
Section: Moments

Difficulty: 1700.0 Banger: 1484.0

Problem

A uniform ladder of length \(l\) and mass \(m\) rests with one end in contact with a smooth ramp inclined at an angle of \(\pi/6\) to the vertical. The foot of the ladder rests, on horizontal ground, at a distance \(l/\sqrt{3}\) from the foot of the ramp, and the coefficient of friction between the ladder and the ground is \(\mu.\) The ladder is inclined at an angle \(\pi/6\) to the horizontal, in the vertical plane containing a line of greatest slope of the ramp. A labourer of mass \(m\) intends to climb slowly to the top of the ladder.
TikZ diagram
  1. Find the value of \(\mu\) if the ladder slips as soon as the labourer reaches the midpoint.
  2. Find the minimum value of \(\mu\) which will ensure that the labourer can reach the top of the ladder.

Solution

TikZ diagram
  1. \begin{align*} \text{N2}(\uparrow): && R_1 + R_2\sin(\frac{\pi}{6})-2mg &= 0 \\ \text{N2}(\rightarrow): && R_2 \cos (\frac{\pi}{6})-F_r &= 0 \\ \overset{\curvearrowleft}{X}: && lmg \cos \tfrac{\pi}{6} - l R_2 \cos \tfrac{\pi}{6} &= 0 \\ \\ \Rightarrow && R_2 &= mg \\ \Rightarrow && R_1 &= 2mg - \frac12mg \\ &&&=\frac32mg \\ \Rightarrow && \frac{\sqrt{3}}2mg - \mu\frac32mg &= 0 \\ \Rightarrow && \mu &= \frac{1}{\sqrt{3}} \end{align*}
  2. \begin{align*} \text{N2}(\uparrow): && R_1 + R_2\sin(\frac{\pi}{6})-2mg &= 0 \\ \overset{\curvearrowleft}{X}: && \frac12 lmg \cos \tfrac{\pi}{6}+xmg \cos \tfrac{\pi}{6} - l R_2 \cos \tfrac{\pi}{6} &= 0 \\ \\ \Rightarrow && R_2 &= mg(\frac{1}2+\frac{x}{l}) \\ \Rightarrow && R_1 &= 2mg - \frac12mg(\frac{1}2+\frac{x}{l}) \\ &&&=(\frac74 - \frac{x}{2l})mg \\ &&&\geq \frac{5}{4}mg\\ \text{N2}(\rightarrow): && R_2 \cos (\frac{\pi}{6})-\mu R_1& \leq 0 \\ \Rightarrow && \frac{\sqrt{3}}2mg - \mu\frac54mg &\leq 0 \\ \Rightarrow && \mu &\geq \frac{2\sqrt{3}}{5} \end{align*}
Rating Information

Difficulty Rating: 1700.0

Difficulty Comparisons: 0

Banger Rating: 1484.0

Banger Comparisons: 1

Show LaTeX source
Problem source
A uniform ladder of length $l$ and mass $m$ rests with one end in contact with a smooth ramp inclined at an angle of $\pi/6$ to the vertical. The foot of the ladder rests, on horizontal ground, at a distance $l/\sqrt{3}$ from the foot of the ramp, and the coefficient of friction between the ladder and the ground is $\mu.$ The ladder is inclined at an angle $\pi/6$ to the horizontal, in the vertical plane containing a line of greatest slope of the ramp. A labourer of mass $m$ intends to climb slowly to the top of the ladder. 
\begin{center}
    \begin{tikzpicture}[scale=1.2]
    % Filled triangle with opacity
    \fill[black, opacity=0.1] (0,5) -- (0,0) -- (3,0) -- cycle;
    
    % Lines
    \coordinate (O) at (0,0);
    \coordinate (Ltop) at (0,5);
    \coordinate (Lbot) at (3,0);
    \coordinate (Lbott) at (3,1);
    \coordinate (Lmet) at ($(Ltop)!0.4!(Lbot)$);
    \coordinate (Lend) at (7,0);
    
    \draw (O) -- (8,0);
    \draw (Lbot) -- (Ltop);
    \draw (Lmet) -- (Lend);
    \draw (Lbot) -- (Lbott);

    \pic [draw, angle radius=1cm, "$\frac{\pi}{6}$"] {angle = Lbott--Lbot--Ltop};
    \pic [draw, angle radius=1cm, "$\frac{\pi}{6}$"] {angle = Lmet--Lend--Lbot};
    \node at (0.5,2.32) {$\text{ramp}$};
    
    % Double arrow
    \draw[<->] ($(Lbot)+(0,-0.5)$) -- ($(Lend)+(0,-0.5)$) ;
    % Label for the double arrow
    \node at ($0.5*(Lbot)+0.5*(Lend)+(0,-0.5)$) [below] {$l\sqrt{3}$};
\end{tikzpicture}
\end{center}
\begin{questionparts}
\item Find the value of $\mu$ if the ladder slips as soon as the labourer reaches the midpoint. 
\item Find the minimum value of $\mu$ which will ensure that the labourer can reach the top of the ladder. 
\end{questionparts}
Solution source
\begin{center}
    \begin{tikzpicture}[scale=1.2]
    % Filled triangle with opacity
    \fill[black, opacity=0.1] (0,5) -- (0,0) -- (3,0) -- cycle;
    
    % Lines
    \coordinate (O) at (0,0);
    \coordinate (Ltop) at (0,5);
    \coordinate (Lbot) at (3,0);
    \coordinate (Lbott) at (3,1);
    \coordinate (Lmet) at ($(Ltop)!0.4!(Lbot)$);
    \coordinate (Lend) at (7,0);
    
    \draw (O) -- (8,0);
    \draw (Lbot) -- (Ltop);
    \draw (Lmet) -- (Lend);
    \draw (Lbot) -- (Lbott);


    \pic [draw, angle radius=1cm, "$\frac{\pi}{6}$"] {angle = Lbott--Lbot--Ltop};
    \pic [draw, angle radius=1cm, "$\frac{\pi}{6}$"] {angle = Lmet--Lend--Lbot};
    \node at (0.5,2.32) {$\text{ramp}$};
    
    % Double arrow
    \draw[<->] ($(Lbot)+(0,-0.5)$) -- ($(Lend)+(0,-0.5)$) ;
    % Label for the double arrow
    \node at ($0.5*(Lbot)+0.5*(Lend)+(0,-0.5)$) [below] {$l\sqrt{3}$};

    \draw[-latex, blue, ultra thick] ($(Lend)!0.5!(Lmet)$) -- ++({0},{-1/2}) node[below] {$mg$};
    \draw[-latex, blue, ultra thick] ($(Lend)!0.4!(Lmet)$) -- ++({0},{-1/2}) node[below] {$mg$};
    \draw[-latex, blue, ultra thick] ($(Lmet)$) -- ++({5/10},{3/10}) node[right] {$R_2$};
    \draw[-latex, blue, ultra thick] ($(Lend)$) -- ++({0},{5/10}) node[above] {$R_1$};
    \draw[-latex, blue, ultra thick] ($(Lend)$) -- ++({-4/10},{0}) node[left, below] {$F_r$};
\end{tikzpicture}
\end{center}

\begin{questionparts}
\item \begin{align*}
\text{N2}(\uparrow): && R_1 + R_2\sin(\frac{\pi}{6})-2mg &= 0 \\
\text{N2}(\rightarrow): && R_2 \cos (\frac{\pi}{6})-F_r &= 0 \\
\overset{\curvearrowleft}{X}: && lmg \cos \tfrac{\pi}{6} - l R_2 \cos \tfrac{\pi}{6} &= 0 \\
\\
\Rightarrow && R_2 &= mg \\
\Rightarrow && R_1 &= 2mg - \frac12mg \\
&&&=\frac32mg \\
\Rightarrow && \frac{\sqrt{3}}2mg - \mu\frac32mg &= 0 \\
\Rightarrow && \mu &= \frac{1}{\sqrt{3}}
\end{align*}

\item \begin{align*}
\text{N2}(\uparrow): && R_1 + R_2\sin(\frac{\pi}{6})-2mg &= 0 \\
\overset{\curvearrowleft}{X}: && \frac12 lmg \cos \tfrac{\pi}{6}+xmg \cos \tfrac{\pi}{6} - l R_2 \cos \tfrac{\pi}{6} &= 0 \\
\\
\Rightarrow && R_2 &= mg(\frac{1}2+\frac{x}{l}) \\
\Rightarrow && R_1 &= 2mg - \frac12mg(\frac{1}2+\frac{x}{l}) \\
&&&=(\frac74 - \frac{x}{2l})mg \\
&&&\geq \frac{5}{4}mg\\
\text{N2}(\rightarrow): && R_2 \cos (\frac{\pi}{6})-\mu R_1& \leq 0 \\
\Rightarrow && \frac{\sqrt{3}}2mg - \mu\frac54mg &\leq 0 \\
\Rightarrow && \mu &\geq \frac{2\sqrt{3}}{5}
\end{align*}

\end{questionparts}