1994 Paper 3 Q9

Year: 1994
Paper: 3
Question Number: 9

Course: UFM Mechanics
Section: Simple Harmonic Motion

Difficulty: 1700.0 Banger: 1500.0

Problem

A smooth, axially symmetric bowl has its vertical cross-sections determined by \(s=2\sqrt{ky},\) where \(s\) is the arc-length measured from its lowest point \(V\), and \(y\) is the height above \(V\). A particle is released from rest at a point on the surface at a height \(h\) above \(V\). Explain why \[ \left(\frac{\mathrm{d}s}{\mathrm{d}t}\right)^{2}+2gy \] is constant. Show that the time for the particle to reach \(V\) is \[ \pi\sqrt{\frac{k}{2g}}. \] Two elastic particles of mass \(m\) and \(\alpha m,\) where \(\alpha<1,\) are released simultaneously from opposite sides of the bowl at heights \(\alpha^{2}h\) and \(h\) respectively. If the coefficient of restitution between the particles is \(\alpha,\) describe the subsequent motion.

No solution available for this problem.

Rating Information

Difficulty Rating: 1700.0

Difficulty Comparisons: 0

Banger Rating: 1500.0

Banger Comparisons: 0

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Problem source
A smooth, axially symmetric bowl has its vertical cross-sections determined
by $s=2\sqrt{ky},$ where $s$ is the arc-length measured from its
lowest point $V$, and $y$ is the height above $V$. A particle is
released from rest at a point on the surface at a height $h$ above
$V$. Explain why 
\[
\left(\frac{\mathrm{d}s}{\mathrm{d}t}\right)^{2}+2gy
\]
is constant. 

Show that the time for the particle to reach $V$ is 
\[
\pi\sqrt{\frac{k}{2g}}.
\]
Two elastic particles of mass $m$ and $\alpha m,$ where $\alpha<1,$
are released simultaneously from opposite sides of the bowl at heights
$\alpha^{2}h$ and $h$ respectively. If the coefficient of restitution
between the particles is $\alpha,$ describe the subsequent motion.