1993 Paper 3 Q10

Year: 1993
Paper: 3
Question Number: 10

Course: LFM Pure
Section: Linear transformations

Difficulty: 1700.0 Banger: 1484.0

Problem

The transformation \(T\) of the point \(P\) in the \(x\),\(y\) plane to the point \(P'\) is constructed as follows: \hfil\break Lines are drawn through \(P\) parallel to the lines \(y=mx\) and \(y=-mx\) to cut the line \(y=kx\) at \(Q\) and \(R\) respectively, \(m\) and \(k\) being given constants. \(P'\) is the fourth vertex of the parallelogram \(PQP'R\). Show that if \(P\) is \((x_1,y_1)\) then \(Q\) is $$ \left( {mx_1-y_1 \over m-k}, {k(mx_1-y_1)\over m-k}\right). $$ Obtain the coordinates of \(P'\) in terms of \(x_1\), \(y_1\), \(m\) and \(k\), and express \(T\) as a matrix transformation. Show that areas are transformed under \(T\) into areas of the same magnitude.

No solution available for this problem.

Rating Information

Difficulty Rating: 1700.0

Difficulty Comparisons: 0

Banger Rating: 1484.0

Banger Comparisons: 1

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Problem source
The transformation $T$ of the point $P$ in the $x$,$y$ plane to
the point $P'$ is constructed as follows:
\hfil\break
Lines are drawn through $P$ parallel to the lines $y=mx$ and $y=-mx$
to cut the line $y=kx$ at $Q$ and $R$ respectively, $m$ and $k$ being
given constants. $P'$ is the fourth vertex of the parallelogram
$PQP'R$. 
Show that if $P$ is $(x_1,y_1)$ then $Q$ is 
$$
\left( {mx_1-y_1 \over m-k}, {k(mx_1-y_1)\over m-k}\right).
$$
Obtain the coordinates of $P'$ in terms of 
$x_1$, $y_1$, $m$ and $k$, and express $T$ as a matrix transformation.
Show that  areas are transformed under $T$ into areas of the same 
magnitude.