Year: 1992
Paper: 3
Question Number: 11
Course: UFM Mechanics
Section: Momentum and Collisions 1
No solution available for this problem.
Difficulty Rating: 1700.0
Difficulty Comparisons: 0
Banger Rating: 1500.0
Banger Comparisons: 0
$\,$
\begin{center}
\begin{tikzpicture}
% Draw vertical lines
\draw (0,0) -- (0,4) node[above] {$A$};
\draw (5,0) -- (5,4) node[above] {$X$};
% Draw horizontal arrow
\draw[->] (0,2) node[left] {$O$} -- (2,2) node[above right] {$V$};
% Add bottom labels
\node[below] at (0,0) {$B$};
\node[below] at (5,0) {$Y$};
\end{tikzpicture}
\end{center}
$AOB$ represents a smooth vertical wall and $XY$ represents a parallel smooth vertical barrier, both standing on a smooth horizontal table. A particle $P$ is projected along the table from $O$ with speed $V$ in a direction perpendicular to the wall. At the time of projection, the distance between the wall and the barrier is $(75/32)VT$, where $T$ is a constant. The barrier moves directly towards the wall, remaining parallel to the wall, with initial speed $4V$ and with constant acceleration $4V/T$ directly away from the wall. The particle strikes the barrier
$XY$ and rebounds. Show that this impact takes place at time $5T/8$.
The barrier is sufficiently massive for its motion to be unaffected by the impact. Given that the coefficient of restitution is $1/2$, find the speed of $P$ immediately after impact.
$P$ strikes $AB$ and rebounds. Given that the coefficient of restitution for this collision is also $1/2,$ show that the next collision of $P$ with the barrier is at time $9T/8$ from the start of the motion.