Year: 1991
Paper: 1
Question Number: 11
Course: UFM Mechanics
Section: Momentum and Collisions 1
No solution available for this problem.
Difficulty Rating: 1500.0
Difficulty Comparisons: 0
Banger Rating: 1500.1
Banger Comparisons: 2
A piledriver consists of a weight of mass $M$ connected to a lighter
counterweight of mass $m$ by a light inextensible string passing
over a smooth light fixed pulley. By considerations of energy or otherwise,
show that if the weights are released from rest, and move vertically,
then as long as the string remains taut and no collisions occur, the
weights experience a constant acceleration of magnitude
\[
g\left(\frac{M-m}{M+m}\right).
\]
Initially the weight is held vertically above the pile, and is released
from rest. During the subsequent motion both weights move vertically
and the only collisions are between the weight and the pile. Treating
the pile as fixed and the collisions as completely inelastic, show
that, if just before a collision the counterweight is moving with
speed $v$, then just before the next collision it will be moving
with speed $mv/\left(M+m\right)$. {[}You may assume that when the
string becomes taut, the momentum lost by one weight equals that gained
by the other.{]}
Further show that the times between successive collisions with the
pile form a geometric progression. Show that the total time before
the weight finally comes to rest is three times the time from the
start to the first impact.