2022 Paper 3 Q9

Year: 2022
Paper: 3
Question Number: 9

Course: UFM Mechanics
Section: Momentum and Collisions 2

Difficulty: 1500.0 Banger: 1500.0

Problem

  1. Two particles \(A\) and \(B\), of masses \(m\) and \(km\) respectively, lie at rest on a smooth horizontal surface. The coefficient of restitution between the particles is \(e\), where \(0 < e < 1\). Particle \(A\) is then projected directly towards particle \(B\) with speed \(u\). Let \(v_1\) and \(v_2\) be the velocities of particles \(A\) and \(B\), respectively, after the collision, in the direction of the initial velocity of \(A\). Show that \(v_1 = \alpha u\) and \(v_2 = \beta u\), where \(\alpha = \dfrac{1 - ke}{k+1}\) and \(\beta = \dfrac{1+e}{k+1}\). Particle \(B\) strikes a vertical wall which is perpendicular to its direction of motion and a distance \(D\) from the point of collision with \(A\), and rebounds. The coefficient of restitution between particle \(B\) and the wall is also \(e\). Show that, if \(A\) and \(B\) collide for a second time at a point \(\frac{1}{2}D\) from the wall, then \[ k = \frac{1+e-e^2}{e(2e+1)}\,. \]
  2. Three particles \(A\), \(B\) and \(C\), of masses \(m\), \(km\) and \(k^2m\) respectively, lie at rest on a smooth horizontal surface in a straight line, with \(B\) between \(A\) and \(C\). A vertical wall is perpendicular to this line and lies on the side of \(C\) away from \(A\) and \(B\). The distance between \(B\) and \(C\) is equal to \(d\) and the distance between \(C\) and the wall is equal to \(3d\). The coefficient of restitution between each pair of particles, and between particle \(C\) and the wall, is \(e\), where \(0 < e < 1\). Particle \(A\) is then projected directly towards particle \(B\) with speed \(u\). Show that, if all three particles collide simultaneously at a point \(\frac{3}{2}d\) from the wall, then \(e = \frac{1}{2}\).

No solution available for this problem.

Examiner's report
— 2022 STEP 3, Question 9
Mean: ~10.3 / 20 (inferred) 33% attempted Inferred 10.3/20 from 'just above half marks' (10+0.3); second-best scoring question; most popular Applied question

The most popular of the Applied questions, with a third of candidates attempting it; it was the second-best scoring question on the paper with a mean score of just above half marks. The question relied mainly on the use of conservation of momentum and Newton's experimental law of impact. Most candidates made a very good start with several scoring full or close to full marks in the first part. The difficulties arose later when dealing with the three-particle situation in part (ii). Very few candidates were able to take a step back and see how this problem linked to part (i), resulting in long pages of algebraic manipulation which were inefficient and rarely correct. A good diagram would have made the link so much more obvious!

One question was attempted by well over 90% of the candidates two others by about 90%, and a fourth by over 80%. Two questions were attempted by about half the candidates and a further three questions by about a third of the candidates. Even the other three received attempts from a sixth of the candidates or more, meaning that even the least popular questions were markedly more popular than their counterparts in previous years. Nearly 90% of candidates attempted no more than 7 questions.

Source: Cambridge STEP 2022 Examiner's Report · 2022-p3.pdf
Rating Information

Difficulty Rating: 1500.0

Difficulty Comparisons: 0

Banger Rating: 1500.0

Banger Comparisons: 0

Show LaTeX source
Problem source
\begin{questionparts}
\item Two particles $A$ and $B$, of masses $m$ and $km$ respectively, lie at rest on a smooth horizontal surface. The coefficient of restitution between the particles is $e$, where $0 < e < 1$. Particle $A$ is then projected directly towards particle $B$ with speed $u$.
Let $v_1$ and $v_2$ be the velocities of particles $A$ and $B$, respectively, after the collision, in the direction of the initial velocity of $A$.
Show that $v_1 = \alpha u$ and $v_2 = \beta u$, where $\alpha = \dfrac{1 - ke}{k+1}$ and $\beta = \dfrac{1+e}{k+1}$.
Particle $B$ strikes a vertical wall which is perpendicular to its direction of motion and a distance $D$ from the point of collision with $A$, and rebounds. The coefficient of restitution between particle $B$ and the wall is also $e$.
Show that, if $A$ and $B$ collide for a second time at a point $\frac{1}{2}D$ from the wall, then
\[ k = \frac{1+e-e^2}{e(2e+1)}\,. \]
\item Three particles $A$, $B$ and $C$, of masses $m$, $km$ and $k^2m$ respectively, lie at rest on a smooth horizontal surface in a straight line, with $B$ between $A$ and $C$. A vertical wall is perpendicular to this line and lies on the side of $C$ away from $A$ and $B$. The distance between $B$ and $C$ is equal to $d$ and the distance between $C$ and the wall is equal to $3d$. The coefficient of restitution between each pair of particles, and between particle $C$ and the wall, is $e$, where $0 < e < 1$. Particle $A$ is then projected directly towards particle $B$ with speed $u$.
Show that, if all three particles collide simultaneously at a point $\frac{3}{2}d$ from the wall, then $e = \frac{1}{2}$.
\end{questionparts}