2011 Paper 3 Q9

Year: 2011
Paper: 3
Question Number: 9

Course: UFM Mechanics
Section: Circular Motion 2

Difficulty: 1700.0 Banger: 1484.0

Problem

Particles \(P\) and \(Q\) have masses \(3m\) and \(4m\), respectively. They lie on the outer curved surface of a~smooth circular cylinder of radius~\(a\) which is fixed with its axis horizontal. They are connected by a light inextensible string of length \(\frac12 \pi a\), which passes over the surface of the cylinder. The particles and the string all lie in a vertical plane perpendicular to the axis of the cylinder, and the axis intersects this plane at \(O\). Initially, the particles are in equilibrium. Equilibrium is slightly disturbed and \(Q\) begins to move downwards. Show that while the two particles are still in contact with the cylinder the angle \(\theta\) between \(OQ\) and the vertical satisfies \[ 7a\dot\theta^2 +8g \cos\theta + 6 g\sin\theta = 10g\,. \]
  1. Given that \(Q\) loses contact with the cylinder first, show that it does so when~\(\theta=\beta\), where \(\beta\) satisfies \[ 15\cos\beta +6\sin\beta =10. \]
  2. Show also that while \(P\) and \(Q\) are still in contact with the cylinder the tension in the string is $\frac {12}7 mg(\sin\theta +\cos\theta)\,$.

No solution available for this problem.

Examiner's report
— 2011 STEP 3, Question 9
Mean: ~8.5 / 20 (inferred) ~17% attempted (inferred) Inferred ~8.5/20: 'slightly less success than Q2' (Q2 ~9.5) → 9.5 - 1.0 = 8.5. Inferred ~17% from 'about a sixth'.

About a sixth of candidates tried this, and on average with slightly less success than question 2. Of the attempts, about a third were close to completely correct, and nearly all the others were barely doing more than grasping at crumbs, reflecting the fact that candidates either did or did not know what they were doing. There was negligible middle ground.

The percentages attempting larger numbers of questions were higher this year than formerly. More than 90% attempted at least five questions and there were 30% that didn't attempt at least six questions. About 25% made substantive attempts at more than six questions, of which a very small number indeed were high scoring candidates that had perhaps done extra questions (well) for fun, but mostly these were cases of candidates not being able to complete six good solutions.

Source: Cambridge STEP 2011 Examiner's Report · 2011-full.pdf
Rating Information

Difficulty Rating: 1700.0

Difficulty Comparisons: 0

Banger Rating: 1484.0

Banger Comparisons: 1

Show LaTeX source
Problem source
Particles $P$ and $Q$ have masses
$3m$ and $4m$, respectively. They
lie on the outer curved surface of a~smooth 
circular cylinder of radius~$a$
which is fixed with its axis horizontal.
They are connected by a light inextensible 
string of length $\frac12 \pi a$, which passes over the 
surface of the cylinder. The particles and the string all lie
in a vertical plane perpendicular to the axis of the cylinder,
and the axis intersects this plane at $O$.
Initially, the particles are in equilibrium.
Equilibrium is slightly disturbed and $Q$  begins to
move downwards. Show that while the two particles
are still in contact with the cylinder the angle $\theta$
between $OQ$ and
the vertical satisfies
\[
7a\dot\theta^2 +8g \cos\theta + 6 g\sin\theta =   10g\,.
\]
\begin{questionparts}
\item
Given that $Q$ loses contact with 
the cylinder first, show that  it does so when~$\theta=\beta$,
where $\beta$ satisfies 
\[
15\cos\beta +6\sin\beta =10.
\] 
\item
Show also that while $P$ and $Q$ are still in contact 
with the cylinder 
the tension in the string is $\frac {12}7 mg(\sin\theta
+\cos\theta)\,$.
\end{questionparts}